# WAEC Further Mathematics Questions 2021 Objective and Theory Update

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** – WAEC Further Mathematics Questions –**

**WAEC Further Mathematics Questions are out now on our website. In this article, I will show you past WAEC Further Mathematics random repeated questions for free. All you need to do is to stay focus and follow this guide.**

West African Examinations Council (WAEC) is an examination board that conducts the West African Senior School Certificate Examination, for University and Jamb entry examination in West African countries.

In a year, over three million candidates registered for the exams coordinated by WAEC.

The 2021 WAEC Further Mathematics exam will comprise Papers 2 & 1 Essay and Objective . That means the examination will last for three hours (3hrs) only.

There will be two papers, papers 1 and 2, that must both be completed.

**PAPER 1**: This paper will contain forty multiple-choice objective questions that will cover the entire course.

Candidates will have one hour to answer all questions for 40 points. The following areas of the curriculum will generate the questions:

30 questions on pure mathematics

4 questions about statistics and probability

6 questions on vectors and mechanics

**PAPER** **2**: There will be two portions, Sections A and B, that must be completed in two hours for 100 points.

Section A will include eight obligatory questions of an elementary kind worth 48 points. The following is how the questions will be distributed:

In this post, we will post samples of the WAEC Further Mathematics questions for candidates that will take partake part in the examination for practice.

**WAEC Further Mathematics Objective Answers**

Today’s WAEC Further Maths OBJ Answers

1-10. CBBDCAADCB

11-20. DCBDCBCDCC

21-30. ABDCDABBCB

31-40. CDCADBCAAD

41-50. ABDCBACDDC

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**Theory Question and Answers**

**(1)** pr(age)=4/5

pr(fully)=3/4

pr(must)=2/3

pr(age not admitted)=1-4/5

=1/5

pr(fully not admitted)=1-3/4

=1/4

pr(must not admitted)=1-2/3

=1/3

Therefore pr(none admitted)=1/5*1/4*1/3

=1/60

**(2)** Tabulate

Marks| 1-10, 11-20, 21-30, 31-40, 41-50,51-60, 61-70, 71-80, 81-90, 91-100

F| 3, 17, 41, 85, 97, 115, 101, 64, 21, 6

C.B| 0.5-105, 10.5-205, 20.5-305, 30.5-405,40.5-505, 50.5-605, 60.5-705, 70.5-805,80.5-905, 90.5-1005

C.F| 0+3=3, 3+17=20, 20+41=61, 61+85=146,146+77=243, 243+115=358, 358+101=459,459+64=523, 523+21=544, 544+6=550

**(3)** Given: f(x)={(4x-x^2)dx

f(x)=2x^2 – x^3/3 + K

f(3)=2(3)^2 – (3)^2/3 + K =21

18 – 9 + K=11

9+K=21

K=21-9

K=12

Therefore, f(x)= -x^3 + 2x^2 + 12

**(4)** 1/1-cos tita + 1/1+cos tita

=1+cos tita + 1-cos tita//(1-cos tita) (1+cos tita) = 2/1+cos tita – cos tita – cos^2 tita = 2/1-cos^2 tita

Recall that :

Cos^2 tita + sin^2 tita = 1

.:. Cos^2 tita = 1-sin^2 tita

.:. 1/1-cos^2 tita + 1/1+cos tita = 2/1-(1-sin^2 tita)

**(5)** At stationary points,

dy/dx=0.

y=x^0(x-3)

Let u=x^2,v=x-3.

du/dx=2x dv/dx=1.

dy/dx= Udv/dx + Vdu/dx

dy/dx=x^2(1)+(x-3)(2x)

.:. dy/dx=x^2+2x^2-6x

dy/dx=3x^2-6x

At stationary point,

dy/dx=0..

.:.3x^2-6x=0

Equation of line=> 3x^2-6x=0

**(6ai)** P:F=4:1 =4x+1x=100

5x=100

x=100/5 x=20

pass=20*4=80%

fail= 20*1=20%

p(pass)=80/100=0.8

p(fail)=20/100=0.2

n=7

**(6aii)** P(between 3 and 6 failed)

P=0.2

q=0.8

P(36)

P(x=3) + P (x=4)+p(x=5)+P(x=6)

p(x=3) 7^C3 (0.2)^3 (0.8)^4

=0.114688

p(x=4)=7^C4 (0.2)^4 (0.8)^3

0.028672

P(x=5)=7^C5 (0.2)^5 (0.8)^2

=0.0043008

P(x=6)=7^C6 (0.2)^6 (0.8)^1

=0.0003584

p(36)

=0.114688+0.028672+0.0043008 +0.0003584 =0.1480192 =0.15(2d.p)

DISCLAIMER! These are not real WAEC Further Mathematics questions but likely repeated questions over the years to help candidate understand the nature of their examinations. Ensure to note every question provided on this page.

**, kindly provide us with your phone number and email address in the comment box below. Also, ask questions pertaining to this guide.**

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